2016년 8월 8일 월요일

The churn ヴェイユ associate same model

The churn ヴェイユ associate same model

It is the basic constitution of the churn ヴェイユ theory, and, in mathematics, the churn ヴェイユ associate same model (British: Chern–Weil homomorphism) is to calculate phase invariant (English version) of vector bundle of smooth manifold (smooth manifold) M and the main bundle in a clause of connection and the curvature expressed with ド Lahm cohomology ring of M. In other words, differential geometry means algebraic topological linkage. The Chen body (Shiing-Shen Chern) since the 1940s-saving and the theory of Andre Weil (AndréWeil) are important steps in the theories of the characteristic kind. This theory is generalization of the theorems of churn - gauss - Bonnet.

It is Lie theory in G I assume を lasting fruit or double bare Lie groups, And Of the top That I express the algebra which the multinomial expression with a に level makes As a substitute for の ) that an identical discussion is possible when I use を. In addition, I meet the next condition under accompanying action (English version) (adjoint action) of を G I assume it the partial algebra which the の fixation point makes. In other words, this partial algebra with all former g of G For のすべての former x, Then, I do it.

The churn ヴェイユ associate same model,-Algebra

It is the の associate same model. Cohomology of this right side is ド Lahm cohomology. For all main bundle on M, such a cohomology exists uniquely. If G is compact; based on this associate same model the cohomology algebra (ring) of classification space BG of the G-bundle the algebra (ring) of the next unchangeable multinomial expression It is the に same model.

(cohomology algebra (ring) of BG is given in a meaning of ド Lahm.

Here であり, I assume it は manifold.) For the non-compact group such as SL(n,R), the cohomology kind that I cannot express by an unchangeable multinomial expression may exist.

Table of contents

Definition of the associate same model

I choose connection form ω of P optionally and assume Ω curvature 2 - form to accompany ω. In other words, it is Ω = Dω, and this is differential calculus outside ω. Oh, with quantic function of degree k that is any complex number a For の former x, であれば, f I assume it the whole of the function that I can consider to be an upper symmetry multiplet type function (I refer to a multinomial expression ring).

Of the を P top

I assume により a 2k-form to be given (with the value of the scalar). vi is 接 vector in P here, は symmetric group Mark of the substitution of the upper 2k unit である (like パフィアン, I refer to operation (English version) (Operations)).

Furthermore, f is unchangeable and is clogged up であれば, But, it is a shut form, and the ド Lahm cohomology of the form can show ω and an independent thing depending on a form on M which is one idea. At first, But, it obeys it from two next lemmas to be a shut form [1].

It is a form on P lemma 1 The form that is one idea on は M I describe を. In other words, a form on M exists, It becomes the への pull return.
If form φ on P is a form on M or is led, lemma 2 is dφ= Dφ.

Actually, as for the Bianchi identical equation, D is differential calculus with the degrees であるので, である. After all lemma 1 But, I mean that I satisfy a premise of lemma 2.

To check lemma 2, Assume it を projection; h When assume it the projection to the の horizontal subspace top; lemma 2 ( The の nucleus is a result of the facts called) fitting it in the just perpendicular subspace. For lemma 1 at first,

I warn であることに. This This is because であり, f are unchangeable. In this way, を formula

I can define により. Here : I assume it the lift of the の option.

Then, of the M top Indicating の ド Lahm cohomology being independent in choice of the connection [2]. I assume it any connection form on を P, I assume it を projection.

とする. Here t Of the top I assume it the function that による is smooth. I assume it の curvature form. When I assume it を inclusion map, It becomes the と homotopic. In this way Oh, by homoTopy equivalent (English version) (homotopy invariance of de Rham cohomology) of the ド Lahm cohomology, I belong to the same ド Lahm cohomology. By uniqueness of after all natural nature and Descente,

であり, に vs. even if do it, become similar. Thus, Oh, I belong to the same cohomology.

In this way, the constitution brings linear representation (I refer to lemma 1).

Actually, the representation can confirm that I am provided in this way,

But, it becomes algebra associate same model (English version) (algebra homomorphism).

An example: Churns and churn index

とし, I assume it をその Lie theory. For x of の each, I can think about the characteristic polynominal which assumes a variable t.

[3] i is the square root of -1 here. Then Oh, because it is the left side of a go board of the expression, It is an upper immutability multinomial expression. k- next churns of the fluent double bare vectors bundle of rank n on manifold M

But, I am given as an image of fk under the churn ヴェイユ associate same model defined by E (I bundle 標構 of E in detail). If it is t = 1, It is は immutability multinomial expression. All churns of E are images of this multinomial expression. In other words,

である.

Direct can show cj from this definition, and this c meets an axiom of churns. For example, by a formula of the harmony among Whitney,

I think about を. I decide to write down curvature 2 - form on M of vector bundle E with Ω here (therefore it is the derivative of the curvature form in the 標構 bundle of E). The churn ヴェイユ associate same model becomes same when I use this Ω. If, here, E is Naokazu of curvature form Ωi of vector bundle Ei and Ei, and, by the words of the line, Ω is block diagonal matrix ΩI on the opposite angle, であるので,

I get を. The product of the right side is the product of the cohomology ring, the cup product (cup product). By a regular voltinism, I can calculate the first churns of the double bare projections straight line (complex projective line). Churns # example: I refer to 複素接 bundle of the Riemannian sphere.

[4] ので,

I get も.

After all the churn index of E,

I am given により. Ω is a curvature form of the connection on E here (because it is Ω はべき zero, the curvature form is a multinomial expression in Ω.) . Therefore, ch is the ring associate same model

である. In a certain ring R including cohomology ring H(M, C), it is factorized the multinomial expression of t

But, I exist. Here λj included in R (these may be called a churn route). Therefore, である.

An example: ポントリャーギン

If E is fluent true vector bundle on M; k- next ポントリャーギン of E,

I am given で. Here 複素化 of E I write と. Is the same thing, but ポントリャーギン, Of the の top

Unchangeable multinomial expression to be given で It is an image by the の churn ヴェイユ associate same model.

Associate same model of the Masanori vector bundle

E on double bare manifolds M when assume it Masanori vector bundle (have a value to complex number), curvature form Ω of E is not a 2-form about a certain L meat measurement; (1, 1) -It is a form (I refer to L meat measurement (Hermitian metrics on a holomorphic vector bundle) in the Masanori vector bundle). Thus, the churn ヴェイユ associate same model premises the following form. に vs. do,

である.

References

  • ^ Kobayashi-Nomizu 1969, Ch. XII.
  • ^ The argument for the independent of a choice of connection here is taken from: Akhil Mathew, Notes on Kodaira vanishing [1]. Kobayashi-Nomizu, the main reference, gives a more concrete argument.
  • The notebook of the ^ editor: This definition becomes t -1 by the documents, but matches it with documents except that I assumed it t here. This choice think normally and has the consistency with the article of churns.
  • ^ proof: Than a definition, Using であるので, Leibniz 則 I calculate の square.

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