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2018년 2월 16일 금요일

UEFA Cup 1984-85

UEFA Cup 1984-85

1984-85won by winning down.

UEFA Cup 1984-85 - - Tournament result Winning | (First time) Second place winner | Competition statistics Scoring the King | József Szabo (8 points) <>

table of contents

First round

Team # 1 Total Team # 2 First Round Round 2
**** 3-1 2-1 1-0
1-3 **** 1-0 0-3
3-4 **** 2-2 1-2
3-4 **** 3-2 0-2
**** 10-0 4-0 6-0
0 - 14 **** 0 - 0 0 - 14
**** 8-3 6-1 2-2
**** 4-2 1-0 3-2
2-5 **** 1-0 1-5
2-3 **** 2-0 0-3
0 - 3 **** 0 - 1 0 - 2
3-7 **** 2-3 1-4
1-3 **** 1-1 0-2
0 - 7 **** 0 - 3 0 - 4
**** 7-3 7-0 0-3
**** 5-2 3-0 2-2
0 - 1 **** 0 - 0 0 - 1
2-7 **** 1-5 1-2
**** 3-2 1-0 2-2
0 - 2 **** 0 - 1 0 - 1
**** 6-2 4-0 2-2
**** () 2-2 1-0 1-2
0 - 4 **** 0 - 2 0 - 2
1-1 () **** 1-0 0-1
**** 5-2 5-0 0-2
2-4 **** 1-0 1-4
0 - 9 **** 0 - 3 0 - 6
0 - 2 **** 0 - 0 0 - 2
**** 4-2 2-0 2-2 ()
1 - 2 **** 1- 0 0 - 2
**** 1-0 1-0 0-0
**** 2-1 2-0 0-1

Second round

Team # 1 Total Team # 2 First Round Round 2
3-7 **** 1-1 2-6
1-1 () **** 1-0 0-1
3-3 () **** 3-2 0-1
2-4 **** 2-1 0-3
**** 2-0 1-0 1-0
**** 3-2 2-1 1-1
**** 6-1 4-0 2-1
**** 4-3 3-0 1-3
2-7 **** 1-2 1-5
1-3 **** 1-1 0-2
3-4 **** 3-1 0-3
2-5 **** 2-4 0-1
0 - 1 **** 0 - 0 0 - 1 ()
6 - 6 () **** 6 - 2 0 - 4
2 - 2 () **** 2- 0 0 - 2
1-4 **** 0-2 1-2

Third round

Team # 1 Total Team # 2 First Round Round 2
1 - 2 **** 1- 0 0 - 2
2-4 **** 2-0 0-4
2 - 2 () **** 2 - 1 0 - 1
**** 5-4 2-2 3-2
4-6 **** 3-0 1-6
**** 3-1 2-0 1-1
**** 5-2 5-0 0-2
1 - 2 **** 0 - 2 1 - 0

Quarter finals

Team # 1 Total Team # 2 First Round Round 2
**** 3-1 2-0 1-1
**** 4-1 1-0 3-1
1-1 () **** 1-0 0-1
0 - 1 **** 0 - 1 0 - 0

Semifinals

Team # 1 Total Team # 2 First Round Round 2
2-3 **** 2-0 0-3
**** 4-3 3-1 1-2

final

For details, see

Team # 1 Total Team # 2 First Round Round 2
1-3 **** 0-3 1-0

footnote

[] - -

1. ****"". UEFA.com. Viewed 30th September 2016.

Related item

  • *

External link

  • *

Acquired from ""

Post Date : 2018-02-16 03:00

This article is taken from the Japanese Wikipedia UEFA Cup 1984-85

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Wikipedia and Tranpedia does not guarantee the accuracy of this document. See our disclaimer for more information.

In addition, This site is simply not responsible for any show is only by translating the writings of foreign licenses that are compatible with CC-BY-SA license information.

2017년 2월 9일 목요일

FA Premier League 1999-2000

FA Premier League 1999-2000

Club stronghold (around London) of Premier League 1999–2000

After FA Premier League 1999-2000 was renewed in a 1992-93 season; Premier League of 8 season eyes. Manchester United gave glory to a straight victory secondary to last season. WimbledonSheffield wens dayWatfordBut, I was demoted.

Refer to "football league 1999-00" for the football league of the season.

Table of contents

Standing

Order Club The number of the games Draw Minus number Profit + /- 勝点 Remarks
1
Manchester United
38
28
7
3
97
45
52
91
UEFA champions league 2000-01, group league
2
Arsenal
38
22
7
9
73
43
30
73
3
Leeds United
38
21
6
11
58
43
15
69
UEFA champions league 2000-01, three rounds of qualifiers
4
Liverpool
38
18
11
9
51
30
21
67
2000-01.1 rounds of UEFA Cup
5
Chelsea
38
18
10
10
53
34
19
65
6
Aston Villa
38
15
13
10
46
35
11
58
UEFA インタートトカップ 2000.3 rounds
7
Sunderland
38
16
10
12
57
56
1
58
8
Leicester City
38
16
7
15
55
55
0
55
2000-01.1 rounds of UEFA Cup
9
West Ham United
38
15
10
13
52
53
-1
55
10
Tottenham Hotspur
38
15
8
15
57
49
8
53
11
Newcastle United
38
14
10
14
63
54
9
52
12
Middlesbrough
38
14
10
14
46
52
-6
52
13
Everton
38
12
14
12
59
49
10
50
14
Coventry City
38
12
8
18
47
54
-7
44
15
Southampton
38
12
8
18
45
62
-17
44
16
Derby County
38
9
11
18
44
57
-13
38
17
Bradford City
38
9
9
20
38
68
-30
36
UEFA インタートトカップ 2000.2 rounds
18
Wimbledon
38
10
12
16
46
74
-28
33
Demotion
19
Sheffield wens day
38
8
7
23
38
70
-32
31
20
Watford
38
6
6
26
35
77
-42
24

play stockinette stitches

Home (line) / away (line) MNU ARS LEE LIV CHE AST SUN LEI WHU TOT NEW MID EVE COV SOT DER BRA WDN SHW WAT
01. Manchester United 1–1 2–0 1–1 3–2 3–0 3–0 2–0 7–1 3–1 5–1 1–0 5–1 3–2 3–3 3–1 4–0 1–1 4–0 4–1
02. Arsenal 1–2 2–0 0–1 2–1 3–1 4–1 2–1 2–1 2–1 0–0 5–1 4–1 3–0 3–1 2–1 2–0 1–1 3–3 1–0
03. Leeds United 0–1 0–4 1–2 0–1 1–2 2–1 2–1 1–0 1–0 3–2 2–0 1–1 3–0 1–0 0–0 2–1 4–1 2–0 3–1
04. Liverpool 2–3 2–0 3–1 1–0 0–0 1–1 0–2 1–0 2–0 2–1 0–0 0–1 2–0 0–0 2–0 3–1 3–1 4–1 0–1
05. Chelsea 5–0 2–3 0–2 2–0 1–0 4–0 1–1 0–0 1–0 1–0 1–1 1–1 2–1 1–1 4–0 1–0 3–1 3–0 2–1
06. Aston Villa 0–1 1–1 1–0 0–0 0–0 1–1 2–2 2–2 1–1 0–1 1–0 3–0 1–0 0–1 2–0 1–0 1–1 2–1 4–0
07. Sunderland 2–2 0–0 1–2 0–2 4–1 2–1 2–0 1–0 2–1 2–2 1–1 2–1 1–1 2–0 1–1 0–1 2–1 1–0 2–0
08. Leicester City 0–2 0–3 2–1 2–2 2–2 3–1 5–2 1–3 0–1 1–2 2–1 1–1 1–0 2–1 0–1 3–0 2–1 3–0 1–0
09. West Ham United 2–4 2–1 0–0 1–0 0–0 1–1 1–1 2–1 1–0 2–1 0–1 0–4 5–0 2–0 1–1 5–4 2–1 4–3 1–0
010. Tottenham Hotspur 3–1 2–1 1–2 1–0 0–1 2–4 3–1 2–3 0–0 3–1 2–3 3–2 3–2 7–2 1–1 1–1 2–0 0–1 4–0
011. Newcastle United 3–0 4–2 2–2 2–2 0–1 0–1 1–2 0–2 2–2 2–1 2–1 1–1 2–0 5–0 2–0 2–0 3–3 8–0 1–0
012. Middlesbrough 3–4 2–1 0–0 1–0 0–1 0–4 1–1 0–3 2–0 2–1 2–2 2–1 2–0 3–2 1–4 0–1 0–0 1–0 1–1
013. Everton 1–1 0–1 4–4 0–0 1–1 0–0 5–0 2–2 1–0 2–2 0–2 0–2 1–1 4–1 2–1 4–0 4–0 1–1 4–2
014. Coventry City 1–2 3–2 3–4 0–3 2–2 2–1 3–2 0–1 1–0 0–1 4–1 2–1 1–0 0–1 2–0 4–0 2–0 4–1 4–0
015. Southampton 1–3 0–1 0–3 1–1 1–2 2–0 1–2 1–2 2–1 0–1 4–2 1–1 2–0 0–0 3–3 1–0 2–0 2–0 2–0
016. Derby County 1–2 1–2 0–1 0–2 3–1 0–2 0–5 3–0 1–2 0–1 0–0 1–3 1–0 0–0 2–0 0–1 4–0 3–3 2–0
017. Bradford City 0–4 2–1 1–2 1–0 1–1 1–1 0–4 3–1 0–3 1–1 2–0 1–1 0–0 1–1 1–2 4–4 3–0 1–1 3–2
018. Wimbledon 2–2 1–3 2–0 1–2 0–1 2–2 1–0 2–1 2–2 1–1 2–0 2–3 0–3 1–1 1–1 2–2 3–2 0–2 5–0
019. Sheffield Wednesday 0–1 1–1 0–3 1–2 1–0 0–1 0–2 4–0 3–1 1–2 0–2 1–0 0–2 0–0 0–1 0–2 2–0 5–1 2–2
020. Watford 2–3 2–3 1–2 2–3 1–0 0–1 2–3 1–1 1–2 1–1 1–1 1–3 1–3 1–0 3–2 0–0 1–0 2–3 1–0

I list the result of the home game of each team.
Seeing from a home team, a draw is a yellow column a red column defeat a blue column victory.

Season record

The number of the 1999/00 season total goals
1,060 goals
One game scoring average
2.78


Score ranking

Other

  • Ashley Cole, Michael Carrick and others make their debut
  • The each generation worst record that season World Cup point 24 that Watford got updates World Cup point 27 that Ipswich Town recorded in a season for 1996-1997 years.
  • I run that this season, FA hold the World Cup that holding in Germany was said to be a rule route in England and it was negative, but I persuade it and dispatch you to the Manchester United in itself participation to FIFA club world championship 2000 performed in Brazil in the process letting you evade an FA cup expressly (extraordinary determination appeared for the holding when FA let you decline it by an English oldest cup war, and Arsene Wenger criticized these measures saying "it is favor"). However, originally England promised not to run between England and Germany in 2006 while Germany did not run for championship holding of 1996 in Europe. These a series of events are opportunities and will reach the remark by the interview that Joseph ブラッター performed on the day before meeting final.

This article is taken from the Japanese Wikipedia FA Premier League 1999-2000

This article is distributed by cc-by-sa or GFDL license in accordance with the provisions of Wikipedia.

Wikipedia and Tranpedia does not guarantee the accuracy of this document. See our disclaimer for more information.

In addition, Tranpedia is simply not responsible for any show is only by translating the writings of foreign licenses that are compatible with CC-BY-SA license information.

2016년 9월 25일 일요일

Multiplier

Multiplier

A multiplier (じょうざんき) is an electronic circuit to multiply it by about two numbers, and there are # digital multiplier and # analog multiplier.

Table of contents

Digital multiplier

By a circuit carrying out multiplication in digital, it is kind of the arithmetic unit.

Various technique is thought about to implement a digital multiplier. Much technique calculates the product of the part which I divided and come true by adding it, and gathering it up. This way is similar to multiplication by the calculation on a piece of paper of 十進整数 to learn in an elementary school. However, I realize it in binary number with the multiplier.

Example in case of the mark no integer

Here, I explain the multiplication of the mark no integer of 8 bits for an illustration. Two numbers that are the input of the multiplier I consider it to be とし, bit sequence. In this case I demand eight partial products by eight times of 1 bit multiplication.Each の bitI am about to be similar. In other words, it Take out の bit; and depending on the value Make のどちらかの bit pattern; is logical product by a bit operationIt is equal to carrying out).

I let you add a partial product as follows to find the final product next.


When I talk in a different way, + の 1 bit left shift + の 2 bits left shift + … + It is equal to の 15 bits left shift, and the product of 16 bits without the mark is finally found.

In the case of a mark integer belonging to, I it

But, it is necessary to let you add a partial product after the mark was expanded when it is a mark integer belonging to. But, when is an integer belonging to mark; of the partial product I do not add を and must go down from other total.

I let some clauses reverse as follows when I let you add it to revise the multiplier which I explained at the top to be able to treat a mark integer by 2 complements belonging to and beat it At the の left edge It makes up for を. It is a minus sign hereIt should be noted a meaning of). This is inversion of the bits not the inversion of the mark. Each partial product The reason why の most significant bit is reversed is that I omit mark expansion. But, the reason why a bit except the top is reversed adversely is that I express subtraction by the addition. This used the property of 2 complements skillfully.


In addition, in the case of minus number, arithmetic overflow occurs, but should ignore both the multiplier and the multiplicand.

Implementation

It was necessary to let you add a partial product using shifter and an accumulator in the old multiplier architecture. In addition, I needed 1 clock cycle to calculate one partial product. The recent multiplier architecture adds all the partial products using Baugh–Wooley algorithm, Wallace tree (English version), en:Dadda multiplier in 1 clock cycle. I can improve it more by reducing the number of partial products which the performance of the Wallace shoe tree multiplier puts the multiplication algorithm of the booth for one of the multiplicand and should add.

Analog multiplier

Multiplication circuit [1] with the transistor

By a circuit carrying out multiplication in analog, I am used for conversion of the frequency band. The general method of implementation I use という equation [2]. The basic principle is next.

  1. With a bipolar transistor I use となることを and get the logarithm of the input signal.
  2. I add it with op-amp.
  3. Like 1 I use を, and 2 takes the index of the sum that was able to appear (this the product of the number of 2).

(but each step really advances approximately instantly because it is an analog circuit.)

The division is possible on a similar principle if I change 2 parts to the subtraction.

Reference

[Help]
  1. ^ Kojima Takada, p. 154.
  2. ^ Shibata 2004, p. 223.

References

Allied item

Outside link

This article is taken from the Japanese Wikipedia Multiplier

This article is distributed by cc-by-sa or GFDL license in accordance with the provisions of Wikipedia.

Wikipedia and Tranpedia does not guarantee the accuracy of this document. See our disclaimer for more information.

In addition, Tranpedia is simply not responsible for any show is only by translating the writings of foreign licenses that are compatible with CC-BY-SA license information.